In an ap a 1 an 20 sn 399

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WebBesides giving the explanation of In an A.P. if a=1,An=20 and Sn=399, then find the value of n.?, a detailed solution for In an A.P. if a=1,An=20 and Sn=399, then find the value of n.? … WebIf an A.P. has a = 1, t n = 20 and s n = 399, then value of n is : If an A.P. has a = 1, t. n. = 20 and s. n. = 399, then value of n is : A. 20. B. 32. C. 38.

In an AP if a = 1, an = 20 and Sn = 399, then n is (A) 19 (B) 21 (C) …

WebIn an AP if a = 1, an = 20 and Sn = 399, then n is (A) 19 (B) 21 (C) 38 (D) 42 Home Get Answers to all your Questions Home NCERT In an AP if a = 1, an = 20 and Sn = 399, then n is (A) 19 (B) 21 (C) 38 (D) 42 #Arithmetic Progressions #NCERT #Maths #Exemplar Maths for Class 10 #1.3 #5.2 #5.3 #5.4 #5.1 #9.2 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 WebIf an AP has a=1, t n=20 and S n=399, then the value of n is A 19 B 32 C 38 D 40 Easy Solution Verified by Toppr Correct option is C) Given, a=1 t n=1+(n−1)d=20 ∴(n−1)d=19 S … images of the 12 days of christmas

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WebIn an AP if a = 1, an = 20 and Sn = 399, then n is _____. CBSE English Medium Class 10. Question Papers 939. Textbook Solutions 33590. MCQ Online Mock Tests 12. Important … WebFeb 14, 2024 · Solution For (2) In an AP if a=1,an =20, and Sn =399,0 then n is equal a=1an =20Sn =399 WebWe can conclude that 10, 20, 30…, 500 is an AP with common difference, d = 10. First term, a = 10. Let the number of terms in this AP = n. Using nth term formula, an = a + (n – 1)d. 500 = 10 + (n – 1)10. 490 = (n – 1)10. n – 1 = 49. n = 50. Sum of an AP, Sn = (n/2) [ a + an], here an is the last term, which is given] = (50/2) ×[10 ... list of c1 drugs

In an AP if a = 1, an = 20 and Sn = 399, then n is (A) 19 (B) 21 (C) …

In an AP, if d = -4, n = 7, an = 4, then a is, a. 6, b. 7, c. 20, d. 28

WebIf in an AP a = 1, t n = 20 and Sn = 399 then n is (a) 19 (b) 21 (c) 38 (d) 42 Report 497 Share Follow Answer peter Reputation: 2.6K University of Lagos, Nigeria 30 July 2024 … WebIn an A.P 1 st term is 1 and the last term is 20. The sum of all terms is =399 then n= .... A 42 B 38 C 21 D 19 Medium Solution Verified by Toppr Correct option is B) The is given that, First term (a)=1 Last term (t n)=20 Sum of terms (S n)=399 We know that, t n=a+(n−1)d S n= 2n(2a+(n−1)d) S n= 2n(a+(a+(n−1)d)) ⇒S n= 2n(a+t n) ⇒399= 2n(1+20) images of the 12 apostlesWebHere d = 19 – 20 = (–1) and S n = 200 Hence, the required number of rows are 16 and in the top row there are 5 logs. 224 Views. Answer . The sum of the third and the seventh terms of an AP is 6 and their product is 8. Find the sum of first sixteen terms of the AP. Let the first term and the common difference of the A .P. be a and d ... images of the 12 days of christmas to print

"WebFeb 27, 2012 · In an AP if a=1, an= 20 and sn =399 then n is a) 13 b) 38 c) 21 - Maths - Arithmetic Progressions - 1833845 Meritnation.com Class-10 » Maths Arithmetic … " - In an ap a 1 an 20 sn 399

In an ap a 1 an 20 sn 399

In an A.P., if a = 1, an = 20 and sn = 399 then n is - Toppr

WebIn an AP if a=1, an =20 and Sn =399, then n is Q. If an AP has a=1, tn=20 and Sn=399, then the value of n is Q. In an AP, if d = - 4 , n = 7 and an = 4, then a is equal to A) 6 B) 7 C) 20 D) … WebSolution: An arithmetic progression (AP) is a sequence where the two consecutive terms have the same common difference. It is obtained by adding the same fixed number to its previous term. The nth term of an AP is. aₙ = a + (n - 1 )d. a = first term. aₙ = nth term. d = common difference. Considering the question, we get the value as,

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WebSum of n terms of AP is given by: S n = n 2 2 a 1 + n-1 d where a 1 = first term, d = common difference. S 24-4 = 24-4 2 2 × 1 + 24-4-1 13 ∵ d = 13, n = 24, a 1 = 1 S 20 = 20 2 2 + 19 × 13 = 2490. a n-4 = a 1 + n-4-1 d a 24-4 = 1 + 24-4-1 13 ∵ d = 13, n = 24, a 1 = 1 a 20 = 248. Therefore, the ordered pair S n-4, a n-4 is equal to (2490 ... WebFeb 11, 2013 · if an ap a=1 ,an=20,sn= 399 then n is Asked by anish mishra 11 Feb, 2013, 02:45: PM Expert Answer Sn=399 => n/2 (a + an) = 399 => n/2 ( 1 + 20) = 399 =>n/2 (21) = 399 => n = 399 X 2/21 => n= 38 Answered by 11 Feb, 2013, 05:49: PM Application Videos This video explains the concept of Arithmetic Progression, Solving Linear E...

WebIf an A.P. has a = 1, t n = 20 and s n = 399, then value of n is : A. 20 B. 32 C. 38 D. 40 Answer: Option C Solution (By Examveda Team) S n = 1 2 ( a + l) × n ⇒ 399 = ( 1 + 20) × n 2 ⇒ 399 × 2 = 21 × n ⇒ n = 399 × 2 21 ⇒ n = 19 × 2 ⇒ n = 38 Join The Discussion Related Questions on Progressions How many terms are there in 20, 25, 30 . . . . . . 140? Web20．（本小题满分14分）已知等差数列 an 的公差d 0，它的前n项和为Sn，若 ... 8 Sn . y2. 1的左、右两个顶点分别为A、B．曲21．（本小题满分14分）已知椭圆x 4. 2. 线C是以A、B. P在第一象限且在曲线C上，直线AP与椭圆相交于另一点T．（1）求曲线C的方程； ...

WebMar 28, 2024 · Objectives: This study aims to investigate the risk factors associated with severity and death from COVID-19 through a systematic review and meta-analysis of the published documents in Iran.Methods: A systematic search was performed based on all articles indexed in Scopus, Embase, Web of Science (WOS), PubMed, and Google Scholar … WebIn an AP, if a = 1, an = 20 and Sn = 399, then n is equal to (a) 19 (b) 21 (c) 38 (d) 42 Solution: Question 18: The sum of first five multiples of 3 is (a) 45 (b) 55 (c) 65 (d) 75 Solution: (a) The first five multiples of 3 are 3, 6, 9,12 and 15. Here, first term, a = 3, common difference, d = 6-3 = 3 and number of terms, n = 5

WebJan 23, 2024 · In an AP if a = 1, an = 20 and Sn = 399, then n is (A) 19 (B) 21 (C) 38 (D) 42. 2Pi classes. 36.7K subscribers.

WebAn arithmetic progression (AP) is a sequence where the two consecutive terms have the same common difference. It is obtained by adding the same fixed number to its previous … images of the 1981 us army bayonet trainingWeb98 Likes, 0 Comments - АВТОМОБИЛЬ•ВЫКУП•ОБМЕН•ПРОДАЖА (@avtomarket04) on Instagram: "⚡️Datsun Mi-Do⚡️ Год выпуска ... images of the 1920s fashionWebIn an AP, if a =1, an, = 20 and Sn = 399, then find n. ← Prev Question Next Question → +1 vote . 6.6k views. asked Feb 1, 2024 in Mathematics by Kundan kumar (51.5k points) In an … images of the 1916 risingWebOct 25, 2015 · In an AP, if a=1,an=20 and Sn= 399, then n=? Advertisement Expert-Verified Answer 603 people found it helpful Brainly User since , an = a+ (n-1)d 20 = 1 + (n-1)d 19 = … images of the 12 greek godsWebSep 20, 2024 · Given : The first term of an A.P. is 1 and the nth term is 20. If Sn = 399 To find : The value of n ? Solution : The sum of n terms of A.P is given by, Where, a is the first term a=1 l is the nth term l=20 =399 is the sum of n terms Substitute the value in the formula, Therefore, the value of n is 38. #Learn more images of the 2016 honda pilotWebMar 19, 2024 · In an AP, if a = 1, an = 20 and Sn = 399, then n is equal to A. 19 B. 21 C. 38 D. 42. asked Aug 25, 2024 in Arithmetic Progression by Sima02 (49.6k points) arithmetic progression; class-10; Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. images of the 1920s gangstersWebLas protecciones eléctricas tienen un papel relevante en la seguridad y en la adecuada operación de un sistema eléctrico de potencia. Particularmente, en el caso de la generación y el trasporte, por su importancia requieren un eficiente sistema de protecciones que permita garantizar la integridad de sus elementos y la continuidad del servicio eléctrico. images of the 19th amendment